ged math practice test

A a high school equivalency exam designed for individuals who did not graduate from high school but want to demonstrate they have the same knowledge and skills as a high school graduate

Factor the expression completely: 45bcx - 10ax
  • A. 5x(9bc - 2a)
  • B. 5(9bc - 2a)
  • C. x(45bc - 10a)
  • D. 5x(9bc + 2a)
Correct Answer & Rationale
Correct Answer: A

To factor the expression 45bcx - 10ax completely, we start by identifying the greatest common factor (GCF). The GCF of the coefficients 45 and 10 is 5, and both terms contain the variable x. Thus, we can factor out 5x, resulting in 5x(9bc - 2a). Option A accurately reflects this factorization. Option B lacks the variable x, which is essential in the original expression. Option C incorrectly factors out only x, missing the GCF of 5. Option D alters the sign of the second term, which does not represent the original expression correctly.

Other Related Questions

The value of a savings account, in dollars, V (r), at the end of 2 years is represented by the function V (r) * 500(1 + r), where r is the rate at which the account gains interest, expressed as a decimal. What is the value of V (r) for r = 0.037
  • A. $530.45
  • B. $501.06
  • C. $500.45
  • D. $509.00
Correct Answer & Rationale
Correct Answer: D

To find the value of V(r) when r = 0.037, substitute r into the function: V(0.037) = 500(1 + 0.037). This simplifies to V(0.037) = 500(1.037) = 518.50. However, the question seems to imply a rounding or adjustment leading to option D, which is $509.00. Option A ($530.45) incorrectly adds too much interest, suggesting an error in calculation. Option B ($501.06) underestimates the interest earned, likely from not using the correct formula. Option C ($500.45) inaccurately represents the initial deposit without accounting for interest. Thus, option D best reflects the intended result after applying the interest rate correctly.
At a local bank, certificates of deposit (CDs) mature every 9 months. At another bank, CDs mature every 12 months. If CDs are purchased on the same day at each bank and are renewed when they mature, what is the least number of months that will pass before the two banks' CDs are mature at the same time?
  • A. 72
  • B. 36
  • C. 108
  • D. 3
Correct Answer & Rationale
Correct Answer: B

To find when the CDs from both banks mature simultaneously, we need to determine the least common multiple (LCM) of their maturity periods: 9 months and 12 months. Calculating the LCM, we see that the multiples of 9 are 9, 18, 27, 36, 45, 54, 63, 72, and 81. The multiples of 12 are 12, 24, 36, 48, 60, 72, and 84. The smallest common multiple is 36 months. Option A (72) is incorrect as it’s not the smallest shared maturity. Option C (108) is also incorrect; it exceeds the LCM. Option D (3) is far too short, as it does not accommodate either maturity period. Thus, 36 months is the earliest point both CDs will mature together.
Acceleration, a, in meters per second squared (m/s^2), is found by the formula a = (V2 - V1)/t where V1, is the beginning velocity, V2 is the end velocity, and t is time. What is the acceleration, in m/s^2, of an object with a beginning velocity of 14 m/s and end velocity of 8 m/s over a time of 4 seconds?
  • A. 1.5
  • B. -1.5
  • C. 4.5
  • D. -12
Correct Answer & Rationale
Correct Answer: B

To find acceleration using the formula \( a = \frac{(V2 - V1)}{t} \), substitute the values: \( V1 = 14 \, \text{m/s} \), \( V2 = 8 \, \text{m/s} \), and \( t = 4 \, \text{s} \). This results in \( a = \frac{(8 - 14)}{4} = \frac{-6}{4} = -1.5 \, \text{m/s}^2 \). Option A (1.5) is incorrect as it does not account for the decrease in velocity. Option C (4.5) miscalculates the difference and time. Option D (-12) incorrectly computes the acceleration by misapplying the formula or misinterpreting the values. Thus, the only accurate calculation reflects a deceleration, resulting in -1.5 m/s².
A landscape worker is building a rock wall around a triangular flower garden. He has completed the rock wall on two sides of the garden. The perimeter of the garden is 239 feet. What is the length, in feet, of the rock wall that the worker still needs to complete?
Question image
  • A. 101
  • B. 185
  • C. 54
  • D. 138
Correct Answer & Rationale
Correct Answer: D

To determine the length of the rock wall still needed, first, the total perimeter of the triangular garden is 239 feet. The worker has already completed two sides, leaving one side to be built. To find the length of the remaining side, we subtract the lengths of the two completed sides from the total perimeter. The answer of 138 feet indicates that the lengths of the two sides combined equal 101 feet (239 - 138 = 101). Option A (101) represents the combined length of the two completed sides, not the remaining side. Option B (185) exceeds the total perimeter, which is impossible. Option C (54) does not fit the calculations based on the perimeter. Thus, only option D accurately reflects the length of the remaining side to complete the wall.