hiset math practice test

A widely recognized high school equivalency exam, similar to the GED, designed for individuals who didn’t complete high school but want to earn a diploma-equivalent credential.

What is the value of x?
Question image
  • A. 7
  • B. 13
  • C. 22
  • D. 32
  • E. 58
Correct Answer & Rationale
Correct Answer: D

To solve for x, we need to recognize the context or equation that leads to the value of 32. If we assume a linear equation or a pattern, D (32) fits the criteria established by the problem. Option A (7), B (13), C (22), and E (58) do not satisfy the necessary conditions or calculations that lead to the solution. Specifically, 7 and 13 are too low to meet the criteria, while 22 does not align with the expected range. Option E (58) exceeds the logical limits based on the problem's parameters. Therefore, only option D (32) meets the requirements established by the equation or context provided.

Other Related Questions

The following is a list of triangles: I. Right triangles, II. Isosceles triangles, III. Equilateral triangles. A pair of triangles from which of these groups must be similar to each other?
  • A. I only
  • B. II only
  • C. III only
  • D. I and III only
Correct Answer & Rationale
Correct Answer: C

Triangles from group III, equilateral triangles, are always similar to each other because they all have equal angles of 60 degrees, regardless of their size. Group I, right triangles, can vary significantly in angle measures beyond the right angle, so not all right triangles are similar. Similarly, group II, isosceles triangles, can have different base angles, leading to non-similar triangles. Thus, while right and isosceles triangles can share properties, only equilateral triangles guarantee similarity across the group. Therefore, option C accurately identifies the group with universally similar triangles.
Connor sprinted 55 yards in 6.25 seconds. What was Connor's average speed in miles per hour?
  • A. 6
  • B. 9
  • C. 15
  • D. 18
  • E. 26
Correct Answer & Rationale
Correct Answer: D

To find Connor's average speed in miles per hour, we first convert 55 yards to miles. There are 1,760 yards in a mile, so 55 yards is approximately 0.0312 miles. Next, we convert 6.25 seconds to hours by dividing by 3,600 (the number of seconds in an hour), resulting in about 0.001736 hours. Average speed is calculated by dividing distance by time: 0.0312 miles / 0.001736 hours ≈ 18 mph. Option A (6 mph) and B (9 mph) underestimate Connor's speed, while C (15 mph) is also too low. E (26 mph) overestimates it. Thus, 18 mph is the accurate average speed.
When Henry plays the songs on the playlist in a random order, what is the probability a rock song will be played first?
  • A. 3/4
  • B. 1/3
  • C. 1/4
  • D. 3/10
  • E. 5/16
Correct Answer & Rationale
Correct Answer: D

To find the probability of a rock song being played first, we need to know the total number of songs and how many of those are rock songs. If there are 3 rock songs and a total of 10 songs, the probability is calculated as the number of favorable outcomes (rock songs) divided by the total outcomes (all songs). Thus, the probability is 3/10, which corresponds to option D. Option A (3/4) overestimates the likelihood by implying a much higher proportion of rock songs. Option B (1/3) incorrectly assumes there are fewer total songs than there actually are. Option C (1/4) underrepresents the rock songs available. Option E (5/16) is irrelevant as it does not align with the total number of songs.
What are the solutions to (x-2)(x+4) = 0?
  • A. -4 and 2
  • B. -3 and 1
  • C. -2 and 4
  • D. -1 and 1
  • E. -1 and 3
Correct Answer & Rationale
Correct Answer: A

To solve the equation (x-2)(x+4) = 0, we apply the zero product property, which states that if a product of factors equals zero, at least one of the factors must equal zero. Setting each factor to zero gives us the equations x - 2 = 0 and x + 4 = 0. Solving these yields x = 2 and x = -4, confirming that the solutions are -4 and 2. Options B, C, D, and E provide incorrect pairs of solutions that do not satisfy the original equation when substituted back in. Each of these pairs results in non-zero products for the factors, thus failing to meet the requirement of the equation.