accuplacer arithmetic full length practice test

Commonly used by colleges and universities to place students into appropriate courses.

Which of the following inequalities is correct?
  • A. 2/3 < 3/5 < 5/7
  • B. 2/3 < 5/7 < 3/5
  • C. 3/5 < 2/3 < 5/7
  • D. 3/5 < 5/7 < 2/3
Correct Answer & Rationale
Correct Answer: C

To determine the order of the fractions, we can convert them to decimals or find a common denominator. - **Option A (2/3 < 3/5 < 5/7)** is incorrect because 2/3 (approximately 0.67) is greater than 3/5 (0.6), violating the first inequality. - **Option B (2/3 < 5/7 < 3/5)** is also incorrect, as 5/7 (approximately 0.71) is greater than 2/3, making the first inequality false. - **Option D (3/5 < 5/7 < 2/3)** is incorrect because, while 3/5 is less than 5/7, 5/7 is greater than 2/3, contradicting the second inequality. - **Option C (3/5 < 2/3 < 5/7)** is accurate; 3/5 is indeed less than 2/3, and 2/3 is less than 5/7, maintaining the correct order.

Other Related Questions

50.50 ÷ 0.25
  • A. 202
  • B. 2.2
  • C. 2.02
  • D. 0.22
Correct Answer & Rationale
Correct Answer: A

To solve 50.50 ÷ 0.25, converting the division into a simpler form is helpful. Dividing both numbers by 0.25 effectively transforms the problem into 50.50 ÷ 0.25 = 50.50 × 4, which equals 202. Option B (2.2) is incorrect as it misrepresents the scale of the division, resulting from a misunderstanding of decimal placement. Option C (2.02) also miscalculates the division, likely stemming from incorrect multiplication or division steps. Option D (0.22) is far too low, indicating a significant error in understanding the relationship between the dividend and divisor.
What is 0.3 percent of 90?
  • A. 0.027
  • B. 0.27
  • C. 0.3
  • D. 2.7
Correct Answer & Rationale
Correct Answer: B

To find 0.3 percent of 90, convert the percentage to a decimal by dividing by 100, resulting in 0.003. Then, multiply 0.003 by 90, yielding 0.27. Option A (0.027) is too small, as it miscalculates the multiplication. Option C (0.3) represents the percentage itself, not the calculated value of 0.3 percent of 90. Option D (2.7) is ten times larger than the correct answer, indicating a misunderstanding of the percent calculation. Thus, B (0.27) accurately represents 0.3 percent of 90.
Harriet took 48 minutes to ride her bike the distance from her house to the town library. If she rode at a constant rate, what fraction of the total distance did she ride in the first 12 minutes?
  • A. 1/4
  • B. 1/3
  • C. 1/2
  • D. 3/4
Correct Answer & Rationale
Correct Answer: A

To determine the fraction of the total distance Harriet rode in the first 12 minutes, we start by recognizing that she took 48 minutes for the entire trip. Riding at a constant rate means that her distance covered is proportional to the time spent riding. In 12 minutes, which is one-fourth of the total 48 minutes, she would have covered one-fourth of the total distance. Thus, the fraction of the total distance she rode in the first 12 minutes is 1/4. Options B (1/3), C (1/2), and D (3/4) misrepresent the proportion of time to total time. Each suggests a greater fraction than what corresponds to 12 minutes relative to 48 minutes, leading to incorrect conclusions about the distance covered.
4/9 (3/16 - 1/12) =
  • A. 5/108
  • B. 5/48
  • C. 2/9
  • D. 20/48
Correct Answer & Rationale
Correct Answer: A

To solve \( \frac{4}{9} \left( \frac{3}{16} - \frac{1}{12} \right) \), first calculate \( \frac{3}{16} - \frac{1}{12} \). Finding a common denominator (48), we convert the fractions: \( \frac{3}{16} = \frac{9}{48} \) and \( \frac{1}{12} = \frac{4}{48} \). Thus, \( \frac{9}{48} - \frac{4}{48} = \frac{5}{48} \). Next, multiply \( \frac{4}{9} \) by \( \frac{5}{48} \): \[ \frac{4 \times 5}{9 \times 48} = \frac{20}{432} = \frac{5}{108} \] Option B (5/48) is incorrect as it misrepresents the multiplication step. Option C (2/9) ignores the subtraction and multiplication entirely. Option D (20/48) fails to simplify the fraction correctly.